Nhận Dạy Calculus AB-BC

Bạn đang tìm kiếm một khóa học chất lượng để học AB-BC Calculus ? Khóa học của chúng tôi chắc chắn là lựa chọn hoàn hảo cho bạn!Với đội ngũ giảng viên có kinh nghiệm và tâm huyết

Kết Quả Học Viên

Go to Blogger edit html and find these sentences.Now replace these sentences with your own descriptions.This theme is Bloggerized by Lasantha Bandara - Premiumbloggertemplates.com.

This is default featured slide 3 title

Go to Blogger edit html and find these sentences.Now replace these sentences with your own descriptions.This theme is Bloggerized by Lasantha Bandara - Premiumbloggertemplates.com.

This is default featured slide 4 title

Go to Blogger edit html and find these sentences.Now replace these sentences with your own descriptions.This theme is Bloggerized by Lasantha Bandara - Premiumbloggertemplates.com.

This is default featured slide 5 title

Go to Blogger edit html and find these sentences.Now replace these sentences with your own descriptions.This theme is Bloggerized by Lasantha Bandara - Premiumbloggertemplates.com.

Saturday, July 1, 2023

DSAT Math For Scoring 750-800 (Part 1)

9:33 AMNo comments

 1. What is the length of major axis of  \frac{{{x^2}}}{5} + \frac{{{y^2}}}{6} = 24

\begin{array}{l} A.{\rm{ }}\sqrt {30} \\ B.{\rm{ 2}}\sqrt {30} \\ C.{\rm{ 4}}\sqrt {30} \\ D.{\rm{ 24}}\\ E.{\rm{ 30}} \end{array}

Solution 

\frac{{{x^2}}}{5} + \frac{{{y^2}}}{6} = 24 \Rightarrow \frac{{{x^2}}}{{120}} + \frac{{{y^2}}}{{144}} = 1

\Rightarrow \left\{ \begin{array}{l} a = \sqrt {120} \\ b = \sqrt {144} \end{array} \right. \Rightarrow 2a = 2\sqrt {120} = 4\sqrt {30}

2. Bob averaged 40 mph going to work and 60 mph going home. What was his average speed for the trip ?      

\begin{array}{l} A.{\rm{ }}44{\rm{ }}mph\\ B.{\rm{ }}46{\rm{ }}mph\\ C.{\rm{ }}48{\rm{ }}mph\\ D.{\rm{ }}50{\rm{ }}mph\\ E.{\rm{ 52 }}mph \end{array}                       

Solution 

\frac{{40 + 60}}{2} = 50{\rm{ }}mph

3. In ∆ABC, AB=2, BC=3 and AC=4. What is the measure of the largest angle to the nearest degree ? 

\begin{array}{l} A.{\rm{ 10}}{{\rm{4}}^ \circ }\\ B.{\rm{ 10}}{{\rm{8}}^ \circ }\\ C.{\rm{ 11}}{{\rm{2}}^ \circ }\\ D.{\rm{ 11}}{{\rm{6}}^ \circ }\\ E.{\rm{ 12}}{{\rm{0}}^ \circ } \end{array}

Solution 

\begin{array}{l} {b^2} = {a^2} + {c^2} - 2ac\cos B \Rightarrow \cos B = \frac{{{a^2} + {c^2} - {b^2}}}{{2ac}} = - \frac{1}{4}\\ \Rightarrow B = {104^ \circ }29' \end{array}

4. If sinx=a, 0 \le x \le {30^ \circ }, what is sin2x in terms of a ?

\begin{array}{l} A.{\rm{ }}a\sqrt {1 + {a^2}} \\ B.{\rm{ }}a\sqrt {1 - {a^2}} \\ C.{\rm{ 2}}a\sqrt {1 + {a^2}} \\ D.{\rm{ 2}}a\sqrt {1 - {a^2}} \\ E.{\rm{ 2}}a\sqrt {4 - {a^2}} \end{array}

Solution 
\begin{array}{l} \cos x = \sqrt {1 - {{\sin }^2}x} = \sqrt {1 - {a^2}} \\ \Rightarrow \sin 2x = 2\sin x\cos x = 2a\sqrt {1 - {a^2}} \end{array}

 6. What are the y intercepts of  3{x^4}{y^2} + {y^2} + 2y = 4xy + 15

A.{\rm{ (0,5) and (0,}} - {\rm{3)}}
B.{\rm{ (0,}} - {\rm{5) and (0,3)}}
C.{\rm{ (0,5) and (0,3)}}
D.{\rm{ (0,}} - {\rm{3) and (0,}} - {\rm{5)}}
E.{\rm{ (0,3) and (0,}} - {\rm{5)}}

Solution 

x = 0 \Rightarrow {y^2} + 2y - 15 = 0 \Rightarrow y = - 5{\rm{ }}and{\rm{ }}3

7. The half-life of titanium-44 is 63 years. After how many years will 1 gram be left of 70 grams titanimum-44 to the nearest year ?

\begin{array}{l} A.{\rm{ 368}}\\ B.{\rm{ 386}}\\ C.{\rm{ 638}}\\ D.{\rm{ 683}}\\ E.{\rm{ 836}} \end{array}
Solution 

8. Bob invested $100,000 and 20 years later it was $500,000. What was the average percent increase per year ?

\begin{array}{l} A.{\rm{ 7}}{\rm{.5\% }}\\ B.{\rm{ 7}}{\rm{.7\% }}\\ C.{\rm{ 7}}{\rm{.9\% }}\\ D.{\rm{ 8}}{\rm{.1\% }}\\ E.{\rm{ 8}}{\rm{.3\% }} \end{array}
Solution 

9. {x^4} - 5{x^2} - 36 = 0. What are the solutions over complex number ?

\begin{array}{l} A.{\rm{ 3, }} - {\rm{2, 2i, }} - 3i\\ B.{\rm{ 3, }} - {\rm{2, 3i, }} - 2i\\ C.{\rm{ 2, }} - 3{\rm{, 2i, }} - 3i \end{array}

\begin{array}{l} D.{\rm{ 3, }} - 3{\rm{, 2i, }} - 2i\\ E.{\rm{ 2, }} - {\rm{2, 3i, }} - 3i \end{array}

Solution 

10. tan θ=3a, 0 \le \theta \le \frac{\pi }{2}, what is cscθ ? 

\begin{array}{l} A.{\rm{ }}\frac{{\sqrt {9{a^2} + 1} }}{{3a}}\\ B.{\rm{ }}\frac{{\sqrt {9{a^2} + 2} }}{{2a}}\\ C.{\rm{ }}\frac{{\sqrt {9{a^2} + 3} }}{a} \end{array}
\begin{array}{l} D.{\rm{ }}\frac{{\sqrt {9{a^2} - 2} }}{{2a}}\\ E.{\rm{ }}\frac{{\sqrt {9{a^2} - 1} }}{{3a}} \end{array}

Solution 




Read More

Pageviews past week