Confidence Interval for Mean

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1. Find 90% percent confidence interval for the mean of a normal distribution with xichma=3 given sample (3.3, -0.3, -0.6, -0.9) . What would be the confidence interval if xichma were unknown ?

Solution

a. Code Python:

b. Code Python:

import numpy as np

import scipy.stats as st

# define sample data

gfg_data = [3.3, -0.3, -0.6, -0.9]

# create 90% confidence interval

st.t.interval(alpha=0.90, df=len(gfg_data)-1,

      loc=np.mean(gfg_data),

      scale=st.sem(gfg_data))

Result: (-1.937561291069545, 2.6875612910695437)

2. The breaking strength in pounds of five speciments of manila rope of diameter 3/16 inch were found to be 660, 460, 540, 580, 550

a. Estimate the mean breaking strength by a 95 percent confidence interval assuming normality ?

b. Estimate the point at which only 5 percent of such speciments would be expected to break. 

c. Estimate xichma^2 by a 90 percent confidence interval; also xich

d. Plot an 81 percent confidence region for the joint estimation of nuy and xich^2; for nuy and xich

 

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